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Oct 7th, 2010, 04:02 AM
#1
transformWsdlLocations WS
Hi All,
Im new to Spring Web Services and was wondering if someone could shed some light on an issue Im having.
I would like to be able to use the transformWsdlLocations so that I do not need to specify the full WSDL location but Im having issues getting this to work.
How does it know what the first part of the Url should be? i.e. the http://localhost:8080/.
The web services Im building will be deployed on a server that has SSL enabled and therefore I need the url to be something like (this is not the actual URL just an example)
https://companyname:port/ApplicationName/WS.wsdl
The only way I could get them to work is by hardcoding the Uri in each ws which makes deploying so much more work.
I also believe that the port it is using is incorrect so does anyone know where it takes this from?
I hope I have made some sence. Any advice is appreciated.
Emma
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Oct 16th, 2010, 01:28 PM
#2
You can create JNDI properties in tomcat context file and access them in spring servlet.xml
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