DefaultWsdl11Definition - WSDL not found

[skr]

We are planning to use spring web service in our application, I am start learning spring-ws.I would like to start Contract first approach specically from Schema.
I have created and deployed successfully in the server.When I typed http://localhost:8080/WebApps/personService/ url I don't find the wsdl.In the console I don't find any error message.I am using Spring 2.5 and Spring 1.5.9, Netbeans 6.8,Tomcat 6.0, jdk 6.I am using spring-ws all,wsdl4j,jaxb spring ws jar files.Please let me know how I fix this.



Spring-Context.xml


<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schem...ring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">

<context:component-scan base-package="org.springbyexample.ws.service" />

<bean id="person" class="org.springframework.ws.wsdl.wsdl11.DefaultW sdl11Definition"
portTypeName="Person"
p:locationUri="http://localhost:8080/WebApps/personService/"
p:requestSuffix="-request"
p:responseSuffix="-response">
<property name="schema">
<bean class="org.springframework.xml.xsd.SimpleXsdSchema "
p:xsd="classpath:resources/person.xsd">
</bean>
</property>
</bean>

<bean class="org.springframework.ws.server.endpoint.mapp ing.PayloadRootAnnotationMethodEndpointMapping">
<description>An endpoint mapping strategy that looks for @Endpoint and @PayloadRoot annotations.</description>
</bean>

<bean class="org.springframework.ws.server.endpoint.adap ter.MarshallingMethodEndpointAdapter">
<description>Enables the MessageDispatchServlet to invoke methods requiring OXM marshalling.</description>
<constructor-arg ref="marshaller"/>
</bean>

<bean id="marshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshalle r"
p:contextPath="schema.domain" />

</beans>



person.xsd


<xsd:schema xmlns="http://www.springbyexample.org/person/schema/beans"
targetNamespace="http://www.springbyexample.org/person/schema/beans"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">

<xsd:element name="get-persons-request">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="name" type="xsd:string" />
</xsd:sequence>
</xsd:complexType>
</xsd:element>

<xsd:element name="person-response">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="person" type="person"
minOccurs="0" maxOccurs="unbounded"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>

<xsd:complexType name="person">
<xsd:sequence>
<xsd:element name="id" type="xsd:int" />
<xsd:element name="first-name" type="xsd:string" />
<xsd:element name="last-name" type="xsd:string" />
</xsd:sequence>
</xsd:complexType>

</xsd:schema>


web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">

<servlet>
<servlet-name>spring-ws</servlet-name>
<servlet-class>org.springframework.ws.transport.http.Messag eDispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:resources/spring-ws-context.xml</param-value>
</init-param>
</servlet>

<servlet-mapping>
<servlet-name>spring-ws</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>

</web-app>

[harish.km]

Have you tried accessing this URL ?

http://localhost:8080/WebApps/personService/person.wsdl

Spring WS provide the WSDL name as the bean id of the DefaultWsdl11Definition.

With the URL what you are looking, the URL if appended with the WSDL file name, then you should be able to view the WSDL.

Hope this is what you are looking for

Cheers!

[skr]

It works fine.Excellent thanks.