SpringFormController HELP NEEDED IMMEDIATELY
Something trivial that I am not getting. :-)
Here is my web.xml:
Code:<?xml version="1.0" encoding="UTF-8"?> <web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <display-name>foo</display-name> <context-param> <param-name>log4jConfigLocation</param-name> <param-value>/WEB-INF/log4j.properties</param-value> </context-param> <context-param> <param-name>log4jRefreshInterval</param-name> <param-value>1000</param-value> </context-param> <listener> <listener-class>org.springframework.web.util.Log4jConfigList ener</listener-class> </listener> <listener> <listener-class>org.springframework.web.context.ContextLoade rListener</listener-class> </listener> <servlet> <servlet-name>dispatch</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherSe rvlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatch</servlet-name> <url-pattern>/send/*</url-pattern> </servlet-mapping> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> </web-app>
Here is my very basic controller:
Code:package com.memestorm.web; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.commons.logging.Log; import org.apache.commons.logging.LogFactory; import org.springframework.validation.BindException; import org.springframework.web.context.support.WebApplica tionContextUtils; import org.springframework.web.servlet.ModelAndView; import org.springframework.web.servlet.mvc.SimpleFormCont roller; import org.springframework.web.servlet.mvc.multiaction.Mu ltiActionController; public class DispatchController extends SimpleFormController { public DispatchController(){ super(); setCommandClass(Product.class); setFormView("edit"); } protected ModelAndView onSubmit(HttpServletRequest request, HttpServletResponse response, Object command, BindException errors) throws Exception { System.out.print(command); return new ModelAndView("result"); } }
Here is my web application context (dispatch-servlet.xml):
Here is the viewform (edit.jsp):Code:<?xml version="1.0" encoding="UTF-8" ?> <!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd"> <beans> <bean id="bigBrotherHandlerInterceptor" class="com.memestorm.web.BigBrotherHandlerIntercep tor" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.Intern alResourceViewResolver"> <property name="prefix"> <value>/WEB-INF/views/</value> </property> <property name="suffix"> <value>.jsp</value> </property> </bean> <bean id="urlMapping" class="org.springframework.web.servlet.handler.Sim pleUrlHandlerMapping"> <property name="interceptors"> <list> <ref local="bigBrotherHandlerInterceptor"/> </list> </property> <property name="mappings"> <props> <prop key="/edit.html">dispatchController</prop> </props> </property> </bean> <bean id="dispatchController" class="com.memestorm.web.DispatchController"> </bean> </beans>
Here is the simple result page:Code:<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%> <%@taglib prefix="c" uri="http://java.sun.com/jstl/core"%> <%@taglib prefix="spring" uri="http://www.springframework.org/tags"%> <% String path = request.getContextPath(); String basePath = request.getScheme() + "://" + request.getServerName() + ":" + request.getServerPort() + path + "/"; %> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <base href="<%=basePath%>"> <title>My JSP 'edit.jsp' starting page</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> </head> <body> <form action="edit.html" method="post"> <table> <tr> <td> Name </td> <td> <spring:bind path="command.name"> <input name="name" value="${status.value}"> <span class="error">${status.errorMessage}</span> </spring:bind> </td> </tr> <tr> <td> Description </td> <td> <spring:bind path="command.description"> <input name="description" value="${status.value}"> <span class="error">${status.errorMessage}</span> </spring:bind> </td> </tr> <tr> <td></td> <td> <input type="submit"> </td> </tr> </table> </form> </body> </html>
Code:<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%> <% String path = request.getContextPath(); String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPor t()+path+"/"; %> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <base href="<%=basePath%>"> <title>My JSP 'result.jsp' starting page</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> </head> <body> Your data has been submitted. <br> </body> </html>
Here is the URL I use to view the form:
localhost:8080 /SpringProj2 /send /edit.html
My browser is redirected to this url after i hit the submit button:
//localhost:8080/ SpringProj2/ edit.html where Tomcat complains it can't find the requested resource.
Note: I have tried to change /send/* to /* in the web.xml at which point it won't even render the form. I can't figure it out. Can you see where I am messing up? Thanks.
Reply With Quote