How can I reference to an XML file which locates in dependency-jar?

[thomas2004]

Hi all,

In my program there is as usual the "spring-servlet.xml" which contains the injections of the classes. But some of the classes are referenced as ref="anotherRef". And the "anotherRef" is in the "applicationContext.xml" in a dependened jar.

How can I reference to this "anotherRef"?

Here is the sample codes.

"spring-servlet.xml" in my program:

...
	<bean id="dslBean" parent="calculator" 
		class="com.mycompany.DslBean">
		<property name="productTemplateFile" value="/products/70010_PBLebenRisiko.xml"></property>
	</bean>
...

The parent="calculator" is defined in "applicationContext.xml" in other jar:

...
	<osgi:reference id="calculator"
		interface="com.othercompany.Calculator" />
...

[mgervais@agaetis.fr]

You can add the applicationContext.xml from your external jar in your web.xml like this:

	<servlet>
		<servlet-name>Spring Servlet</servlet-name>
		<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
		<init-param>
			<param-name>contextConfigLocation</param-name>
			<param-value>classpath:applicationcontextinclasspath.xml applicationcontextinwebinf.xml</param-value>
		</init-param>
	</servlet>

Spring can find resources in classpath, this is posible due to the prefix "classpath".

[thomas2004]

My program is a Spring WS. My "web.xml" looks as follow:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
	version="2.4">
	<display-name>Archetype Created Web Application</display-name>

	<!--  -->
	<servlet>
		<servlet-name>context</servlet-name>
		<servlet-class>org.springframework.web.context.ContextLoaderServlet</servlet-class>
		<load-on-startup>1</load-on-startup>
	</servlet>
	
	<!--  -->
	<servlet>
		<servlet-name>spring-ws</servlet-name>
		<servlet-class>org.springframework.ws.transport.http.MessageDispatcherServlet</servlet-class>
		<init-param>
			<param-name>transformWsdlLocations</param-name>
			<param-value>true</param-value>
		</init-param>
		<load-on-startup>1</load-on-startup>
	</servlet>
	<servlet-mapping>
		<servlet-name>spring-ws</servlet-name>
		<url-pattern>/*</url-pattern>
	</servlet-mapping>
</web-app>

Here you can see I use the MessageDispatcherServlet and transformWsdlLocations. I am not sure if it will work using your method.

[mgervais@agaetis.fr]

It should work because

http://static.springframework.org/spring-ws/sites/1.5/apidocs/org/springframework/ws/transport/http/MessageDispatcherServlet.html

extends

org.springframework.web.servlet.FrameworkServlet

which handle config file location.

[thomas2004]

I tried as follow:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
	version="2.4">
	<display-name>Archetype Created Web Application</display-name>

	<!--  -->
	<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>/WEB-INF/applicationContext.xml</param-value>
	</context-param>
	
	<!--  -->
	<listener>
		<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
	</listener>

	<!--  -->
	<servlet>
		<servlet-name>spring-ws</servlet-name>
		<servlet-class>org.springframework.ws.transport.http.MessageDispatcherServlet</servlet-class>
		<init-param>
			<param-name>transformWsdlLocations</param-name>
			<param-value>true</param-value>
		</init-param>
		<load-on-startup>1</load-on-startup>
	</servlet>
	<servlet-mapping>
		<servlet-name>spring-ws</servlet-name>
		<url-pattern>/*</url-pattern>
	</servlet-mapping>
</web-app>

[thomas2004]

I think my problem is not 100% solved.

With my code I posted yesterday shown above. I can just access the *.xml file under src/main/webapp/WEB-INF. But as I want to access the *.xml file under scr/main/resources/META-INF, I get exception of FileNotFound. Here is my code:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
	version="2.4">
	<display-name>Archetype Created Web Application</display-name>

	<!--  -->
	<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>classpath:../resources/META-INF/spring/applicationContext.xml</param-value>
	</context-param>
	
	<!--  -->
	<listener>
		<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
	</listener>

	<!--  -->
	<servlet>
		<servlet-name>spring-ws</servlet-name>
		<servlet-class>org.springframework.ws.transport.http.MessageDispatcherServlet</servlet-class>
		<init-param>
			<param-name>transformWsdlLocations</param-name>
			<param-value>true</param-value>
		</init-param>
		<load-on-startup>1</load-on-startup>
	</servlet>
	<servlet-mapping>
		<servlet-name>spring-ws</servlet-name>
		<url-pattern>/*</url-pattern>
	</servlet-mapping>
</web-app>

I try also:

...
	<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>../resources/META-INF/spring/applicationContext.xml</param-value>
	</context-param>

I get the same exception.

Someone has idea?

[mgervais@agaetis.fr]

Did you try this:

	
<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>classpath:/META-INF/spring/applicationContext.xml(2) /WEB-INF/applicationContext.xml (1)</param-value>
	</context-param>

The first (1) is the file in your project and the second(2) is the file in the classpath. I think you should not put "resources" in the path, because META-INF is in the root dir of the jar file.

[thomas2004]

Thanks! I got it this time.