Hello!
I'm running spring ldap 1.1.
I have entries in my e-directory that has cn=foo/1 and cn=foo/2. It works in e-directory.
But when I do a search in spring-ldap that returns such an entry I get:
Caused by: org.springframework.ldap.BadLdapGrammarException: Not a proper name (such as key=value): "cn=foo/1 at org.springframework.ldap.support.LdapRdn.parseLdap (LdapRdn.java:119)
at org.springframework.ldap.support.LdapRdn.<init>(Ld apRdn.java:64)
at org.springframework.ldap.support.DistinguishedName .parse(DistinguishedName.java:132)
at org.springframework.ldap.support.DistinguishedName .<init>(DistinguishedName.java:88)
at org.springframework.ldap.support.DefaultDirObjectF actory.stripBasePath(DefaultDirObjectFactory.java: 90)
at org.springframework.ldap.support.DefaultDirObjectF actory.getObjectInstance(DefaultDirObjectFactory.j ava:54)
at javax.naming.spi.DirectoryManager.createObjectFrom Factories(DirectoryManager.java:218)
at javax.naming.spi.DirectoryManager.getObjectInstanc e(DirectoryManager.java:197)
at com.sun.jndi.ldap.LdapSearchEnumeration.createItem (LdapSearchEnumeration.java:105)
What to do?


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