Newbie in Spring FrameWork Please Help ...

**abu taha** · Jul 4th, 2012, 04:14 AM

Hi ...

My Company gives me a task to learn about Spring Framework MVC and ORM Modules and evaluate if we can implement it in our tasks in the future ..

i began with code :

Code:

<servlet>
  	<servlet-name>springapp</servlet-name>
  	<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
  	<load-on-startup>1</load-on-startup>
  </servlet>
  
  <servlet-mapping>
  	<servlet-name>springapp</servlet-name>
  	<url-pattern>*.htm</url-pattern>
  </servlet-mapping>

Code:

<beans xmlns="http://www.springframework.org/schema/beans"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

	<bean name="hello.htm" class="springapp.web.HelloController" >
		
	</bean>
</beans>

Code:

package springapp.web;

import javax.servlet.http.*;
import javax.servlet.ServletException;

import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.Controller;

import org.apache.commons.logging.LogFactory;
import org.apache.commons.logging.Log;

import java.io.IOException;
import java.util.Date;

public class HelloController implements Controller{

	protected Log logger = LogFactory.getLog(getClass());
	@Override
	public ModelAndView handleRequest(HttpServletRequest request,
			HttpServletResponse response) throws IOException, ServletException {
		
		
		String now = (new Date()).toString();
		logger.info("======== to Hello.jsp modle it then view it "+now+"===");
		return new ModelAndView("hello.jsp", "now", now);
	}
	
	

}

Code:

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
    <%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%@ taglib prefix="fmt" uri="http://java.sun.com/jsp/jstl/fmt" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
	<h1>Spring Tutorial</h1>
	<p>Greetings <c:out value="${now}"></c:out></p>
</body>
</html>

and the result when i run the url "http:localhost:8080/SpringApp/hello.htm" is

Code:

org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/SpringApp/hello.htm] in DispatcherServlet with name 'springapp'

**Marten Deinum** · Jul 4th, 2012, 05:19 AM

I suggest a read of the reference guide especially the web section.

In short your bean name is wrong it should be prefixed with a / .

Thread: Newbie in Spring FrameWork Please Help ...

Thread Tools

Display

Newbie in Spring FrameWork Please Help ...

Posting Permissions