Hello all, I'm trying to run an application to bench a call to HttpInvoker.
I'd like to run spring without config file to minimize the startup time. It should as fast as an EJB call.
So here is my test:
myClass is null so I think this object RemoteInvocation should be defined precisely but I don't know how.Code:HttpInvokerProxyFactoryBean ht = new HttpInvokerProxyFactoryBean(); ht.setServiceUrl("http://192.168.X.X:8080/XXX/Services/XXX"); ht.setServiceInterface(MyClass.class); HttpInvokerClientConfiguration htC = new HttpInvokerClientConfiguration() { public String getServiceUrl() { return "http://192.168.X.X:8080/XXX/Services/XXX"; } public String getCodebaseUrl() { return null; } }; RemoteInvocation remo = new RemoteInvocation(); RemoteInvocationResult reqR = ht.getHttpInvokerRequestExecutor().executeRequest(htC, remo); final IMyClass myClass = (IMyClass)reqR.getValue();
Any idea about how I can do this?
Thank you


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