Spring for server side code + webservice

[Sayaly]

Yes i have deployed it in war file..

This is the hierarchy: /WEB-INF/
beans.xml
context.xml
web.xml
The web and beans.xml file is being accessed...why is it then giving me exception in context.xml??

This is my beans.xml file:
<bean id="ear.context" class="org.springframework.context.support.ClassPa thXmlApplicationContext">
<constructor-arg index="0">
<list>
<value>/WEB-INF/context.xml</value>
</list>
</constructor-arg>
</bean>

It seems that constructor of ClassPathXmlApplicationContext cannot get context.xml file right..???
How do i solve this probelm??

[venosov]

Hi, do you have in your web.xml this?:

	<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
	<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>/WEB-INF/context.xml</param-value>
	</context-param>

[Sayaly]

My web.xml file:

<web-app id="WebApp">
	<display-name>Project</display-name>

	<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>/WEB-INF/bean.xml</param-value>
	</context-param>	

	<listener>
		<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
	</listener>
</web-app>

my bean.xml file:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xsi:schemaLocation="http://www.springframework.org/schema/beans
						http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
	<bean id="ear.context" class="org.springframework.context.support.ClassPathXmlApplicationContext">
		<constructor-arg>
		<value>/WEB-INF/context.xml</value>
		</constructor-arg>
	</bean>
</beans>

My context.xml file:

<bean id="login" class="Trial.Controller">
	</bean>

The Controller class contains code to update database...


Error:

SEVERE: Context initialization failed
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'ear.context' defined in ServletContext resource [/WEB-INF/bean.xml]: Instantiation of bean failed; nested exception is org.springframework.beans.BeanInstantiationException: Could not instantiate bean class [org.springframework.context.support.ClassPathXmlApplicationContext]: Constructor threw exception; nested exception is org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [WebContent/WEB-INF/acontext.xml]; nested exception is java.io.FileNotFoundException: class path resource [WebContent/WEB-INF/acontext.xml] cannot be opened because it does not exist
	at org.springframework.beans.factory.support.ConstructorResolver.autowireConstructor(ConstructorResolver.java:254)
	at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.autowireConstructor(AbstractAutowireCapableBeanFactory.java:925)
	at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBeanInstance(AbstractAutowireCapableBeanFactory.java:835)
	at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:440)
	at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409)
	at java.security.AccessController.doPrivileged(Native Method)
	at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380)
	at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264)
	at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222)

[venosov]

OK, instead of referencing context.xml in bean.xml, you should define it in web.xml :

<servlet>
  <servlet-name>appServlet</servlet-name>
  <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
  <init-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/context.xml</param-value>
  </init-param>
  <load-on-startup>1</load-on-startup>
</servlet>

If you'd like to see a complete example, see this.

[Sayaly]

hey thanks..
i saw the complete example and tried to map my problem...
i defined context.xml in web.xml file..
but it is still giving the same error...

from web.xml the bean.xml file is loaded properly i guess...
from the bean.xml file when passes constructor argument(context.xml) to ClassPathXmlApplicationContext its throwing error right??
its there in WEB-INF folder..i matched the spellling too...
Please help with the error..

[venosov]

Why do you define this?

	<bean id="ear.context" class="org.springframework.context.support.ClassPathXmlApplicationContext">
		<constructor-arg>
		<value>/WEB-INF/context.xml</value>
		</constructor-arg>
	</bean>

You can define directly your beans in bean.xml, for example: https://github.com/SpringSource/spri...et-context.xml

[Sayaly]

In github example...it is a complete springproject with all the views defined in WebContent itself.

I am done with UI part for my project using android and server coding using servlet and other java files.
Without disturbing the UI , i am just trying to convert the server side to one which fits in springwork.

[Sayaly]

hey...
<bean id="ear.context" class="org.springframework.context.support.ClassPa thXmlApplicationContext">
<constructor-arg>
<value>file:C:\Users\User\workspace\WebProjectTria l\WebContent\WEB-INF\context.xml</value>
</constructor-arg>
</bean>

adding the entire path..its working fine.... but is it the correct way??
anyways atleast i got something working...

How do we set the classpath of any WebProject...??
http://static.springsource.org/sprin...resources.html

[venosov]

No, it isn't the correct way, you can define your trial.Controller in bean.xml, you should learn the basic concepts first, see again the link:

courses.coreservlets.com/Course-Materials/pdf/spring/basics/03-Spring-in-Web-Apps.pdf

you'll see what you need (applicationContext.xml)

[michal26]

You can use Spring REST to create a Restful webservice.