It turns out I was not looking high enough up the stack, and the real exception is java.lang.ClassNotFoundException: sun.net.www.protocol.https.Handler. This appears to be a runtime library...
Type: Posts; User: hal10001; Keyword(s):
It turns out I was not looking high enough up the stack, and the real exception is java.lang.ClassNotFoundException: sun.net.www.protocol.https.Handler. This appears to be a runtime library...
I have no problems deploying the Sparklr sample project for OAuth 1.0 using 1.0.5.RELEASE. However, independently deploying the Tonr sample gives me a ClassNotFoundException for...
Please use code tags around your code and configuration files so it is easier to read on the forum.
Please post the applicationContext.xml so the bean configurations can be reviewed.
I'm fairly...
Nobody can offer any insights on this? Or at least give me an indication of a better place to ask?
Per the documentation for Tomcat 6.0:
If all you're looking to do is configure a directory path as a string, then there are several ways to accomplish this, but adding a Tomcat context would...
Your application is not configured correctly. You should have one application context that contains beans that are "universal" to your application, while you can have many dispatcher servlets...
8.2. Fail fast mode
I'm looking for where I might configure this option in Spring, but I'm not sure this is a part of JSR 303 so much as it is a Hibernate configuration for their own validator...
I just found this:
http://forum.springsource.org/showthread.php?t=84913
Which links to this:
https://jira.springframework.org/browse/SPR-6437
Unless someone can provide some further...
Hibernate's validator is my JSR-303 provider in my Spring MVC application. When I use @Valid, and then use the JSR-303 annotations on the form object fields, it validates just fine. However, there...
It turns out the problem was that the controller I was redirecting to was not actually configured correctly. So even though it was properly redirecting, the controller it redirected to could not find...
My view resolver:
<bean id="htmlView" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/views" />
<property...
I have to use a Dynamic Web Project instead, or else when I try to add a new Tomcat server a Spring Project will not be available as a resource. Is there a way to get Eclipse to recognize a Spring...