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I try add folowing code in servlet.xml that I find in book Spring in action second edition:



<bean id="endpointExceptionResolver"...

I will try

yes I know that it isnt well formed but how can I check it in my project ?
If client send me SOAP message that isnt valid with xsd it send soapfault

<SOAP-ENV:Fault>
...

Is there method to send whole soap message not just the body ? because If I send SOAP message it doesnt work

java.lang.AssertionError: Messages are different, org.custommonkey.xmlunit.Diff...

ako solved then i change url to this:

<soap:address location="http://google.com/anythig" />

it works...

Hi,
I need help. I programmed one ws and now I am testing it. I must solve all excpetion. How can I solve exception with non valid XML ? When I try to send non valid xml using for example soapUI it...

Hi guys I have small problem

I set this in my web.xml:

<init-param>
<param-name>transformWsdlLocations</param-name>
<param-value>true</param-value>
...