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Hello,
I have a Spring CXF WebService which works fine when no exception is raised. But when I have an exception the response I have in SOAPUI is not the expected one. I think there is a...

I'm working on a WebApp and I have some constraints: Spring 2 + jdk 1.3 + Websphere 4 + J2EE 1.2.
I have the following problem with the Xerces parser,
When I use the Websphere xerces.jar...

I think, for this king of scenario, you can use only only one FormController to handle each request.

You should also paste pieces of your source code to be sure that your problem is correctly...

The rootDao class could be HibernateDaoSupport or a class that extends it, so if we have


class RootDaoImpl extends HibernateDaoSupport{
}

I think it is correct.

First of all I think you have to create a rootDAO class



class RootDaoImpl extends HibernateDAOSupport{


}

class CustomerDaoHibernateImpl extends RootDaoImpl implements CustomerDao {

Why don't you try this?



<bean id="rootDao" class="RootDaoImpl" abstract="true">
<property name="hibernateTemplate">
<ref bean="hibernateTemplate"/>
</property>
</bean>

I hope it could help


<bean id="rootDao" class="RootDaoImpl" abstract="true">
<property name="hibernateTemplate">
<ref bean="hibernateTemplate"/>
</property>
</bean>

I remove bean initilization using an init-method:


<bean id="sessionFactoriesInitializer"
class="SessionFactoriesInitializerImpl"
scope="singleton"
depends-on="dataSource">
</bean>...

Can somebody tell me how can I do to register bean dynamically in application context.

I tried this:


<bean id="sessionFactoriesInitializer"
class="SessionFactoriesInitializerImpl" ...

An esiest way to solve your problem is to define an a class implementing ApplicationContextAware and then inherits the class everywhere you wan the context to bean available.


<beans>

...

I want to register some beans dynamically in the application context, and the following is responsable of it "sessionFactoriesInitializer", the implementation is provided in register() method.

...

No the job request could even join a pending list to be processed another day, and my purpose is to still have the hability to monitor this kind of informations.

No the job request could even join a pending list to be processed another day, and my purpose is to still have the hability to monitor this kind of informations.

This thread is closed because I just forgot to wire the task using the timerFactory

The response that I want to send will just have some information about the status of the submited job and the job identifier, because after sending a job submission request I want to monitor the job...

I have a web application and I want to run some JDK timer tasks, tasks are correctly define in spring files, but when I deploy the war application there is no action, tasks does'nt starts. Is it...

I have seen the example, and some aspects are now clear but I still have a little question.
Just consider the simpleTaskletJob and think that the fileName to process is coming from a web service,...

This is my use case:
- I receive job demands through a WebService, and have to run a business job passing some input data coming from the WebService request.

Notes that I can run the same job...