spring mvc error

javax.servlet.ServletException: No adapter for handler [com.user.logindetails.LoginController@1b47bff]: Does your handler implement a supported interface like Controller?

javax.servlet.ServletException: No adapter for handler [com.user.logindetails.LoginController@1b47bff]: Does your handler implement a supported interface like Controller?
at org.springframework.web.servlet.DispatcherServlet. getHandlerAdapter(DispatcherServlet.java:1091)
at org.springframework.web.servlet.DispatcherServlet. doDispatch(DispatcherServlet.java:874)
at org.springframework.web.servlet.DispatcherServlet. doService(DispatcherServlet.java:809)
at org.springframework.web.servlet.FrameworkServlet.p rocessRequest(FrameworkServlet.java:571)
at org.springframework.web.servlet.FrameworkServlet.d oGet(FrameworkServlet.java:501)
at javax.servlet.http.HttpServlet.service(HttpServlet .java:690)
at javax.servlet.http.HttpServlet.service(HttpServlet .java:803)
at org.apache.catalina.core.ApplicationFilterChain.in ternalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.do Filter(ApplicationFilterChain.java:206)
at org.jboss.web.tomcat.filters.ReplyHeaderFilter.doF ilter(ReplyHeaderFilter.java:96)
at org.apache.catalina.core.ApplicationFilterChain.in ternalDoFilter(ApplicationFilterChain.java:235)
at org.apache.catalina.core.ApplicationFilterChain.do Filter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invo ke(StandardWrapperValve.java:230)
at org.apache.catalina.core.StandardContextValve.invo ke(StandardContextValve.java:175)
at org.jboss.web.tomcat.security.SecurityAssociationV alve.invoke(SecurityAssociationValve.java:182)
at org.jboss.web.tomcat.security.JaccContextValve.inv oke(JaccContextValve.java:84)
at org.apache.catalina.core.StandardHostValve.invoke( StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke (ErrorReportValve.java:102)
at org.jboss.web.tomcat.service.jca.CachedConnectionV alve.invoke(CachedConnectionValve.java:157)
at org.apache.catalina.core.StandardEngineValve.invok e(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.servic e(CoyoteAdapter.java:262)
at org.apache.coyote.http11.Http11Processor.process(H ttp11Processor.java:844)
at org.apache.coyote.http11.Http11Protocol$Http11Conn ectionHandler.process(Http11Protocol.java:583)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run( JIoEndpoint.java:446)
at java.lang.Thread.run(Thread.java:662)

below is dispatcher-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"
xmlns:p="http://www.springframework.org/schema/p">

<bean id="viewResolver"
class="org.springframework.web.servlet.view.Intern alResourceViewResolver">
<property name="prefix">
<value>/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<bean id="myurlMapping" class="org.springframework.web.servlet.handler.Sim pleUrlHandlerMapping">
<property name="interceptors">
<list>
<ref local="localeChangeInterceptor" />
</list>
</property>
<property name="mappings">
<props>
<prop key="/login.html">loginController</prop>
</props>
</property>
</bean>

<bean id="datasource" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName">
<value>com.mysql.jdbc.Driver</value></property>
<property name="url" value="jdbc:mysql://localhost:8080/hibernatetutorial"/>
<property name="username" value="root"/>
<property name="password" value="root"/>

</bean>
<bean id="jdbctemplate" class="org.springframework.jdbc.core.JdbcTemplate" >
<constructor-arg>
<ref local="datasource"/>
</constructor-arg>
</bean>
<bean id="loginmodel" class="com.user.logindetails.LoginModel">
<constructor-arg>
<ref local="jdbctemplate"/>
</constructor-arg>
</bean>
<bean id="loginController" class="com.user.logindetails.LoginController">

<property name="loginmodel">
<ref local="loginmodel"/>
</property>
<property name="commandName">
<value>user</value>
</property>
<property name="commandClass">
<value>com.user.logindetails.user</value>
</property>

</bean>

<bean id="localeChangeInterceptor"
class="org.springframework.web.servlet.i18n.Locale ChangeInterceptor">
<property name="paramName" value="hl" />
</bean>

<bean id="localeResolver"
class="org.springframework.web.servlet.i18n.Sessio nLocaleResolver" />
</beans>

Please use [ code][/code ] tags when posting code, that way it remains readable.

I also doubt it is the full configuration (either that or you are mixing spring versions ). So please post the Controller code and all relevant MVC configuration.

i have sent the controller and mode java file and dispatcher-servlet.xml.please resolve my error
Logincontroller.java
package com.user.logindetails;
import org.springframework.validation.BindException;
import org.springframework.web.portlet.ModelAndView;
import org.springframework.web.portlet.mvc.AbstractComman dController;
import org.springframework.web.portlet.mvc.Controller;

import javax.portlet.ActionRequest;
import javax.portlet.ActionResponse;
import javax.portlet.RenderRequest;
import javax.portlet.RenderResponse;
import javax.servlet.http.*;

public class LoginController extends AbstractCommandController implements Controller{
LoginModel loginmodel;


public LoginModel getLoginmodel() {
return loginmodel;
}

public void setLoginmodel(LoginModel loginmodel) {
this.loginmodel = loginmodel;
}

protected ModelAndView handle(HttpServletRequest req,HttpServletResponse res, Object comand, BindException ex)
throws Exception
{
String type=loginmodel.validate((user)comand);
if(type==null)
return new ModelAndView("/login.jsp");
else if(type.equals("jitu"))
return new ModelAndView("/success.jsp");
else
return new ModelAndView("/success.jsp");

}


protected void handleAction(ActionRequest arg0, ActionResponse arg1,
Object arg2, BindException arg3) throws Exception {
// TODO Auto-generated method stub

}


protected ModelAndView handleRender(RenderRequest arg0,
RenderResponse arg1, Object arg2, BindException arg3)
throws Exception {
// TODO Auto-generated method stub
return null;
}



}


lloginmodel.java
package com.user.logindetails;

import org.springframework.jdbc.core.JdbcTemplate;

public class LoginModel {

private JdbcTemplate jdbctemplate;

public LoginModel(JdbcTemplate jt) {
super();
// TODO Auto-generated constructor stub
jdbctemplate=jt;

}
public String validate(user users)
{
try
{
return(String)jdbctemplate.queryForObject("select type from user where username=\'"+users.getUsername()+"\' and userpass=\'"+users.getPassword()+"\'", String.class);
}catch(Exception e){System.out.println(e.getMessage());}
return null;
}


}

As mentioned before use [ code][/code ] tags when posting code, that way it remains readable!? :mad: :mad:

1) Why does your controller extend AbstractCOmmandController AND implements an interface?
2) Your controller appears to be a servlet.controller and a portlet.controller?!
3) NEVER NEVER NEVER use string concat to construct a query this makes you vulnerable to sql injection (although not related to your problem)
4) You are using a servlet HandlerMapping with a portlet controller... Not going to work.
5a) I assume you want to use portlets you need the SimplePortletHandlerAdapterto be able to execute the controller
5b) If it is a servlet you want change your controller

Also what has this to do with spring workflow?!